(4z^2)-(12z)-7=0

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Solution for (4z^2)-(12z)-7=0 equation:


Simplifying
(4z2) + -1(12z) + -7 = 0

Remove parenthesis around (12z)
(4z2) + -1 * 12z + -7 = 0

Multiply -1 * 12
(4z2) + -12z + -7 = 0

Reorder the terms:
-7 + -12z + (4z2) = 0

Solving
-7 + -12z + (4z2) = 0

Solving for variable 'z'.

Factor a trinomial.
(-1 + -2z)(7 + -2z) = 0

Subproblem 1

Set the factor '(-1 + -2z)' equal to zero and attempt to solve: Simplifying -1 + -2z = 0 Solving -1 + -2z = 0 Move all terms containing z to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -2z = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -2z = 0 + 1 -2z = 0 + 1 Combine like terms: 0 + 1 = 1 -2z = 1 Divide each side by '-2'. z = -0.5 Simplifying z = -0.5

Subproblem 2

Set the factor '(7 + -2z)' equal to zero and attempt to solve: Simplifying 7 + -2z = 0 Solving 7 + -2z = 0 Move all terms containing z to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -2z = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -2z = 0 + -7 -2z = 0 + -7 Combine like terms: 0 + -7 = -7 -2z = -7 Divide each side by '-2'. z = 3.5 Simplifying z = 3.5

Solution

z = {-0.5, 3.5}

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